2x^2+5x-700=0

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Solution for 2x^2+5x-700=0 equation: 



2x^2+5x-700=0

a = 2; b = 5; c = -700;
Δ = b2-4ac
Δ = 52-4·2·(-700)
Δ = 5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5625}=75$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-75}{2*2}=\frac{-80}{4}
=-20
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+75}{2*2}=\frac{70}{4}
=17+1/2
$

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